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58x^2+1000x-160=0
a = 58; b = 1000; c = -160;
Δ = b2-4ac
Δ = 10002-4·58·(-160)
Δ = 1037120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1037120}=\sqrt{64*16205}=\sqrt{64}*\sqrt{16205}=8\sqrt{16205}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1000)-8\sqrt{16205}}{2*58}=\frac{-1000-8\sqrt{16205}}{116} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1000)+8\sqrt{16205}}{2*58}=\frac{-1000+8\sqrt{16205}}{116} $
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